Aldehydes and ketones with at least one \( \alpha \)-hydrogen can undergo an aldol reaction due to the acidity of the \( \alpha \)-hydrogens.
This acidity allows the formation of an enolate ion, which then attacks the carbonyl carbon of another molecule, leading to the aldol product.
Therefore, Statement I is correct.
Benzaldehyde does not contain an \( \alpha \)-hydrogen, so it cannot form an enolate ion.
However, ethanol (in this context, likely meaning acetaldehyde) does have \( \alpha \)-hydrogens and can participate in the aldol reaction with itself or with other compounds that can form enolate ions.
Thus, a cross-aldol product can form between benzaldehyde and acetaldehyde (ethanal).
Therefore, Statement II is incorrect.
Statement I is correct, but Statement II is incorrect. The correct answer is Option (4).
Explain with the help of chemical reactions: (I) Acetone is treated with semicarbazide.
Let \( y^2 = 12x \) be the parabola and \( S \) its focus. Let \( PQ \) be a focal chord of the parabola such that \( (SP)(SQ) = \frac{147}{4} \). Let \( C \) be the circle described by taking \( PQ \) as a diameter. If the equation of the circle \( C \) is: \[ 64x^2 + 64y^2 - \alpha x - 64\sqrt{3}y = \beta, \] then \( \beta - \alpha \) is equal to:
The expression given below shows the variation of velocity \( v \) with time \( t \): \[ v = \frac{At^2 + Bt}{C + t} \] The dimension of \( A \), \( B \), and \( C \) is:
The dimensions of a physical quantity \( \epsilon_0 \frac{d\Phi_E}{dt} \) are similar to [Symbols have their usual meanings]
