Aldehydes and ketones with at least one \( \alpha \)-hydrogen can undergo an aldol reaction due to the acidity of the \( \alpha \)-hydrogens.
This acidity allows the formation of an enolate ion, which then attacks the carbonyl carbon of another molecule, leading to the aldol product.
Therefore, Statement I is correct.
Benzaldehyde does not contain an \( \alpha \)-hydrogen, so it cannot form an enolate ion.
However, ethanol (in this context, likely meaning acetaldehyde) does have \( \alpha \)-hydrogens and can participate in the aldol reaction with itself or with other compounds that can form enolate ions.
Thus, a cross-aldol product can form between benzaldehyde and acetaldehyde (ethanal).
Therefore, Statement II is incorrect.
Statement I is correct, but Statement II is incorrect. The correct answer is Option (4).
Would you expect benzaldehyde to be more reactive or less reactive in nucleophilic addition reactions than propanal? Justify your answer.
Match the following List-I with List-II and choose the correct option: List-I (Compounds) | List-II (Shape and Hybridisation) (A) PF\(_{3}\) (I) Tetrahedral and sp\(^3\) (B) SF\(_{6}\) (III) Octahedral and sp\(^3\)d\(^2\) (C) Ni(CO)\(_{4}\) (I) Tetrahedral and sp\(^3\) (D) [PtCl\(_{4}\)]\(^{2-}\) (II) Square planar and dsp\(^2\)
Let A be a 3 × 3 matrix such that \(\text{det}(A) = 5\). If \(\text{det}(3 \, \text{adj}(2A)) = 2^{\alpha \cdot 3^{\beta} \cdot 5^{\gamma}}\), then \( (\alpha + \beta + \gamma) \) is equal to: