- Aqueous KOH favors nucleophilic substitution (SN1/SN2) reactions, where OH− acts as a nucleophile, forming alcohols.
- Alcoholic KOH, due to the presence of alkoxide ions (RO−), is a stronger base and favors the elimination (E2) reaction, leading to alkene formation.
Would you expect benzaldehyde to be more reactive or less reactive in nucleophilic addition reactions than propanal? Justify your answer.