Question:

Given below are two statements:
Statement I : According to the Ellingham diagram, any metal oxide with higher ΔG° is more stable than the one with lower ΔG°.
Statement II :The metal involved in the formation of oxide placed lower in the Ellingham diagram can reduce the oxide of a metal placed higher in the diagram.
In the light of the above statements, choose the most appropriate answer from the options given below

Updated On: Jul 6, 2024
  • Both Statement I and Statement II are correct.
  • Both Statement I and Statement II are incorrect.
  • Statement I is correct but Statement II is incorrect.
  • Statement I is incorrect but Statement II is correct.
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The Correct Option is D

Solution and Explanation

Ellingham diagram is plot of ΔGΔG  vs T.
The criterion for the feasibility of a thermal reduction is that at a given temperature Gibbs energy change of a reaction must be negative. The change in Gibbs energy,ΔG for any process at any specified temperature, is given by the equation
ΔG=ΔHTΔS\Delta G = \Delta H - T \Delta S
where ΔH = enthalpy change and ΔSΔS = entropy change
According to the ellingham diagram, any metal oxide with higher ΔG° has a tendency of getting reduced by the metal whose metal oxide has lower value of ΔG°.
Therefore, Statement I is incorrect but Statement II is correct.

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