Question:

Bonds present in Nitrogen molecule are

Updated On: Apr 28, 2025
  • 1σ and 2π
  • 2π and 2σ
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The Correct Option is B

Approach Solution - 1

The nitrogen molecule (N2) is a diatomic molecule consisting of two nitrogen atoms. To understand the bonding, consider the electronic configuration of a nitrogen atom, which is 1s2 2s2 2p3. Each nitrogen has five valence electrons.

When two nitrogen atoms form a molecule, they share three pairs of electrons to complete their octets, forming a triple bond. This triple bond comprises:

  • One sigma (σ) bond: This bond is formed by the head-on overlap of two sp orbitals (or in some texts, p-orbitals) from each nitrogen atom.
  • Two pi (π) bonds: These bonds are formed by the side-by-side overlap of the remaining unhybridized p orbitals from each nitrogen atom.

Therefore, the correct type of bonds in a nitrogen molecule is one sigma (σ) bond and two pi (π) bonds.

In conclusion, the bonds present in a nitrogen molecule are categorized as 1σ and 2π.

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Approach Solution -2

Explanation:
A nitrogen molecule (\(N_2\)) consists of two nitrogen atoms bonded by a triple bond. This triple bond includes:

  • 1 sigma (σ) bond
  • 2 pi (π) bonds

So, the bonding in \(N_2\) is:
\(N \equiv N\) → one σ and two π bonds.

Hence, the correct answer is: 1σ and 2π.

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