Question:

Given below are two statements: 
Statement I: A homoleptic octahedral complex, formed using monodentate ligands, will not show stereoisomerism 
Statement II: cis- and trans-platin are heteroleptic complexes of Pd. 
In the light of the above statements, choose the correct answer from the options given below

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- Homoleptic complexes have only one type of ligand - Geometrical isomerism requires different spatial arrangements - Cis/trans-platin are classic examples of geometrical (not optical) isomerism - Platinum (Pt) complexes \(\neq\) Palladium (Pd) complexes
Updated On: Nov 7, 2025
  • Both Statement I and Statement II are false
  • Statement I is true but Statement II is false
  • Statement I is false but Statement II is true
  • Both Statement I and Statement II are true
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The Correct Option is B

Approach Solution - 1

Let's evaluate each statement individually to determine their truthfulness.

  • Statement I: A homoleptic octahedral complex, formed using monodentate ligands, will not show stereoisomerism. 
    Explanation: A homoleptic complex is one where all ligands are the same. In the case of octahedral complexes with monodentate ligands, since all positions around the central metal ion are occupied by identical ligands, no spatial variation can exist, thus eliminating the possibility of forming stereoisomers. Therefore, Statement I is true.
  • Statement II: cis- and trans-platin are heteroleptic complexes of Pd. 
    Explanation: Cisplatin and Transplatin are well-known complexes of Platinum (Pt), not Palladium (Pd). Moreover, in these complexes, both chloride ions (Cl) and ammonia molecules (NH3) serve as ligands, making them heteroleptic because they contain different types of ligands. However, the correct metal is Platinum (Pt), not Palladium (Pd). Thus, Statement II is false.

Conclusion: Based on the above explanations, the correct answer is: Statement I is true but Statement II is false.

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Approach Solution -2

Analysis of Statement I:
- A homoleptic octahedral complex with monodentate ligands (e.g., \([Co(NH_3)_6]^{3+})\) has identical ligands in all positions - No geometrical or optical isomers possible as all positions are equivalent - Therefore, Statement I is true
Analysis of Statement II:
- cis-platin and trans-platin are actually Pt(II) complexes, not Pd - Both are homoleptic complexes (contain same ligands: \([PtCl_2(NH_3)_2])\) - The difference is in ligand arrangement (cis/trans), not heteroleptic nature - Therefore, Statement II is false
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