Graphite is the most stable allotrope of carbon and its formation is assigned a zero enthalpy value, as this is used as the reference in thermodynamic calculations. The stability of graphite at standard conditions (298 K and 1 atm) justifies this assignment.
Thus, both statements (A) and (R) are correct, and the reason is the correct explanation of the assertion.
Therefore, the correct answer is \( \boxed{1} \).