Understanding the effect of Earth's rotation on gravity.
Due to the rotation of the Earth, the effective acceleration due to gravity is given by: \[ g_{\text{eff}} = g - \omega^2 R \cos^2 \theta \] Where \( \theta \) is the angle made with the equator.
At the poles, where \( \theta = 90^\circ \), the change in gravity is zero because \( \cos(90^\circ) = 0 \). This shows no effect on the poles. For the equator, where \( \theta = 0^\circ \), the change in gravity is maximum: \[ g_{\text{eff}} = g - \omega^2 R \] Thus, the change in gravity is maximum at the equator and zero at the poles.
This contradicts Statement II, but Statement I is correct.
Let \( \alpha = \dfrac{-1 + i\sqrt{3}}{2} \) and \( \beta = \dfrac{-1 - i\sqrt{3}}{2} \), where \( i = \sqrt{-1} \). If
\[ (7 - 7\alpha + 9\beta)^{20} + (9 + 7\alpha - 7\beta)^{20} + (-7 + 9\alpha + 7\beta)^{20} + (14 + 7\alpha + 7\beta)^{20} = m^{10}, \] then the value of \( m \) is ___________.