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from the top of the tower 60 mts high the angle of
Question:
From the top of the tower 60 mts high the angle of depression of two objects due north and due south of the tower are 60° and 45° then the distance between two objects is 60
TS POLYCET - 2020
TS POLYCET
Updated On:
Apr 17, 2025
\(60\sqrt 3\ m\)
\((60+20\sqrt 3)\ m\)
\(60(\sqrt 3-1)\ m\)
\(60(\sqrt 3+1)\ m\)
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The Correct Option is
D
Solution and Explanation
The correct option is (D):
\(60(\sqrt 3+1)\ m\)
.
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