Question:
From the top of the tower 60 mts high the angle of depression of two objects due north and due south of the tower are 60° and 45° then the distance between two objects is 60
From the top of the tower 60 mts high the angle of depression of two objects due north and due south of the tower are 60° and 45° then the distance between two objects is 60
Updated On: Apr 29, 2024
- \(60\sqrt 3\ m\)
- \((60+20\sqrt 3)\ m\)
- \(60(\sqrt 3-1)\ m\)
- \(60(\sqrt 3+1)\ m\)
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The Correct Option is D
Solution and Explanation
The correct option is (D): \(60(\sqrt 3+1)\ m\).
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