Question:
For given cell, at T K
Pt | H2(g) | H+ || Fe3+ ; Fe2+ | Pt
( 1 bar ) ( 1 M )
Ecell = .712 V
E°cell = .770 V
if \(\frac{[Fe^{2+}]}{[Fe^{3+}]}\) is t \((\frac{2.303\ RT}{F}=.058)\)
then find \((\frac{t}{5})\)
For given cell, at T K
Pt | H2(g) | H+ || Fe3+ ; Fe2+ | Pt
( 1 bar ) ( 1 M )
Ecell = .712 V
E°cell = .770 V
if \(\frac{[Fe^{2+}]}{[Fe^{3+}]}\) is t \((\frac{2.303\ RT}{F}=.058)\)
then find \((\frac{t}{5})\)
Pt | H2(g) | H+ || Fe3+ ; Fe2+ | Pt
( 1 bar ) ( 1 M )
Ecell = .712 V
E°cell = .770 V
if \(\frac{[Fe^{2+}]}{[Fe^{3+}]}\) is t \((\frac{2.303\ RT}{F}=.058)\)
then find \((\frac{t}{5})\)
Updated On: Mar 28, 2024
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Correct Answer: 2
Solution and Explanation
The correct answer is : 2
.712 = .770 - \(\frac{.058}{2}\log[\frac{Fe^{2+}}{Fe^{3+}}]^2\)
-.058 = .-058 \(\log\frac{[Fe^{2+}]}{[Fe^{3+}]}\)
\(\frac{Fe^{2+}}{Fe^{3+}}=10=t\)
\(\frac{t}{5}=2\)
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