Question

For given cell, at T K
Pt | H₂(g) | H⁺ || Fe³⁺ ; Fe²⁺ | Pt
   ( 1 bar ) ( 1 M )
E_cell = .712 V
E^°_cell = .770 V
if \(\frac{[Fe^{2+}]}{[Fe^{3+}]}\) is t \((\frac{2.303\ RT}{F}=.058)\)
then find \((\frac{t}{5})\)

Answer 1

Correct Answer: 2

The correct answer is : 2
.712 = .770 - \(\frac{.058}{2}\log[\frac{Fe^{2+}}{Fe^{3+}}]^2\)
-.058 = .-058 \(\log\frac{[Fe^{2+}]}{[Fe^{3+}]}\)
\(\frac{Fe^{2+}}{Fe^{3+}}=10=t\)
\(\frac{t}{5}=2\)