To solve the problem, we need to evaluate the expression and determine the correct number of significant figures in the result. The given expression is:
\(y = \frac{32.3 \times 1125}{27.4}\)
To determine the final number of significant figures, follow these steps:
Therefore, the value of \(y\) should be reported as:
This solution uses correct significant figure rules and arithmetic to arrive at the answer \(y = 1330\), matching the given correct option.
Given the experimental expression:
\[ y = \frac{32.3 \times 1125}{27.4}, \] where all the digits are significant.
The number of significant figures in each of the values is: - \( 32.3 \) has 3 significant figures. - \( 1125 \) has 4 significant figures. - \( 27.4 \) has 3 significant figures. According to the rules of significant figures: - When multiplying or dividing, the result should have the same number of significant figures as the value with the fewest significant figures. Therefore, the result should have 3 significant figures.
First, calculate the expression: \[ y = \frac{32.3 \times 1125}{27.4} \approx \frac{36337.5}{27.4} \approx 1330.05. \]
Rounding to 3 significant figures gives: \[ y \approx 1330. \]
The value of \( y \) should be reported as \( \boxed{1330} \).
| List - I(Number) | List - II(Significant figure) |
| (A) 1001 | (I) 3 |
| (B) 010.1 | (II) 4 |
| (C) 100.100 | (III) 5 |
| (D) 0.0010010 | (IV) 6 |
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is: