Question:

For a series LCR circuit, I vs ω curve is shown :

(a) To the left of ωr, the circuit is mainly capacitive.

(b) To the left of ωr, the circuit is mainly inductive.

(c) At ωr, impedance of the circuit is equal to the resistance of the circuit.

(d) At ωr, impedance of the circuit is 0.

 To the left of ωr, the circuit is mainly capacitive.

Choose the most appropriate answer from the options given below.

Updated On: Mar 19, 2025
  • (a) and (d) only
  • (b) and (d) only
  • (a) and (c) only
  • (b) and (c) only
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The Correct Option is C

Solution and Explanation

The correct option is(C): (a) and (c) only

We know that

\(X_c=\frac{1}{wC}\)

and XL = ωL

Also, at ω = ωr : XL = XC

⇒ For ω<ωr : capacitive

and At

\(w=w_r:z=\sqrt{R^2+(X_L-X_C)^2}=R\)

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Concepts Used:

LCR Circuit

An LCR circuit, also known as a resonant circuit, or an RLC circuit, is an electrical circuit consist of an inductor (L), capacitor (C) and resistor (R) connected in series or parallel.

Series LCR circuit

When a constant voltage source is connected across a resistor a current is induced in it. This current has a unique direction and flows from the negative to positive terminal. Magnitude of current remains constant.

Alternating current is the current if the direction of current through this resistor changes periodically. An AC generator or AC dynamo can be used as AC voltage source.