A | B | Y |
0 | 0 | 1 |
0 | 1 | 0 |
1 | 0 | 1 |
1 | 1 | 0 |
To find the expression for the output Y, we analyze the truth table:
A | B | Y |
---|---|---|
0 | 0 | 1 |
0 | 1 | 0 |
1 | 0 | 1 |
1 | 1 | 0 |
We look for the rows where Y is 1:
- When A=0 and B=0, Y=1.
- When A=1 and B=0, Y=1.
From the first row, we have A'B' (where A' and B' represent the complements of A and B, respectively).
From the third row, we have AB'.
Therefore, the expression for Y is the sum of these two terms:
Y = A'B' + AB'
We can simplify this expression:
Y = B'(A' + A)
Since A' + A = 1, we have:
Y = B' * 1
Y = B'
So, the expression for the output Y is B'.
Final Answer:
B'
A | B | Y |
0 | 0 | 1 |
0 | 1 | 0 |
1 | 0 | 1 |
1 | 1 | 0 |
Find output voltage in the given circuit.
A bob of heavy mass \(m\) is suspended by a light string of length \(l\). The bob is given a horizontal velocity \(v_0\) as shown in figure. If the string gets slack at some point P making an angle \( \theta \) from the horizontal, the ratio of the speed \(v\) of the bob at point P to its initial speed \(v_0\) is :