A | B | Y |
0 | 0 | 1 |
0 | 1 | 0 |
1 | 0 | 1 |
1 | 1 | 0 |
To find the expression for the output Y, we analyze the truth table:
A | B | Y |
---|---|---|
0 | 0 | 1 |
0 | 1 | 0 |
1 | 0 | 1 |
1 | 1 | 0 |
We look for the rows where Y is 1:
- When A=0 and B=0, Y=1.
- When A=1 and B=0, Y=1.
From the first row, we have A'B' (where A' and B' represent the complements of A and B, respectively).
From the third row, we have AB'.
Therefore, the expression for Y is the sum of these two terms:
Y = A'B' + AB'
We can simplify this expression:
Y = B'(A' + A)
Since A' + A = 1, we have:
Y = B' * 1
Y = B'
So, the expression for the output Y is B'.
Final Answer:
B'
A | B | Y |
0 | 0 | 1 |
0 | 1 | 0 |
1 | 0 | 1 |
1 | 1 | 0 |
Find output voltage in the given circuit.
Consider a water tank shown in the figure. It has one wall at \(x = L\) and can be taken to be very wide in the z direction. When filled with a liquid of surface tension \(S\) and density \( \rho \), the liquid surface makes angle \( \theta_0 \) (\( \theta_0 < < 1 \)) with the x-axis at \(x = L\). If \(y(x)\) is the height of the surface then the equation for \(y(x)\) is: (take \(g\) as the acceleration due to gravity)
A constant voltage of 50 V is maintained between the points A and B of the circuit shown in the figure. The current through the branch CD of the circuit is :