A | B | Y |
0 | 0 | 1 |
0 | 1 | 0 |
1 | 0 | 1 |
1 | 1 | 0 |
To find the expression for the output Y, we analyze the truth table:
A | B | Y |
---|---|---|
0 | 0 | 1 |
0 | 1 | 0 |
1 | 0 | 1 |
1 | 1 | 0 |
We look for the rows where Y is 1:
- When A=0 and B=0, Y=1.
- When A=1 and B=0, Y=1.
From the first row, we have A'B' (where A' and B' represent the complements of A and B, respectively).
From the third row, we have AB'.
Therefore, the expression for Y is the sum of these two terms:
Y = A'B' + AB'
We can simplify this expression:
Y = B'(A' + A)
Since A' + A = 1, we have:
Y = B' * 1
Y = B'
So, the expression for the output Y is B'.
Final Answer:
B'
From the truth table, we get the simplified expression: Y = A + B.
The given options align best with the simplified form B, confirming the answer.
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R.
Assertion A : The potential (V) at any axial point, at 2 m distance(r) from the centre of the dipole of dipole moment vector
\(\vec{P}\) of magnitude, 4 × 10-6 C m, is ± 9 × 103 V.
(Take \(\frac{1}{4\pi\epsilon_0}=9\times10^9\) SI units)
Reason R : \(V=±\frac{2P}{4\pi \epsilon_0r^2}\), where r is the distance of any axial point, situated at 2 m from the centre of the dipole.
In the light of the above statements, choose the correct answer from the options given below :
The output (Y) of the given logic gate is similar to the output of an/a :