The binding energy equation is essential in nuclear physics to understand stability
Step 1: Analyze the terms in the binding energy equation.
$E_B = a_v A - a_s A^{2/3} - a_c \frac{Z(Z-1)}{A^{1/3}} - a_a \frac{(A-2Z)^2}{A} + \delta(A, Z)$.
- Volume term: $a_v A$
- Surface energy term: $-a_s A^{2/3}$
- Coulomb term: $-a_c \frac{Z(Z-1)}{A^{1/3}}$
- Asymmetry term: $-a_a \frac{(A-2Z)^2}{A}$
- Pairing term: $\delta(A, Z)$
Step 2: Match the options with the equation.
- C and D are directly supported by the equation.
Final Answer: The most appropriate choice is option (3).
Consider a water tank shown in the figure. It has one wall at \(x = L\) and can be taken to be very wide in the z direction. When filled with a liquid of surface tension \(S\) and density \( \rho \), the liquid surface makes angle \( \theta_0 \) (\( \theta_0 < < 1 \)) with the x-axis at \(x = L\). If \(y(x)\) is the height of the surface then the equation for \(y(x)\) is: (take \(g\) as the acceleration due to gravity) 

In the first configuration (1) as shown in the figure, four identical charges \( q_0 \) are kept at the corners A, B, C and D of square of side length \( a \). In the second configuration (2), the same charges are shifted to mid points C, E, H, and F of the square. If \( K = \frac{1}{4\pi \epsilon_0} \), the difference between the potential energies of configuration (2) and (1) is given by: