Given, \(α_n = 19^n – 12^n\)
Let equation of roots \(12\) & \(19\) i.e.
\(x^2−31x+228=0\)
Where, \(x = 19\) or \(12\)
Thus,
\(\frac {31α_9−α_{10}}{57α_8}=\frac {31(199−129)−(1910−1210)}{57(198−128)}\)
\(=\frac {199(31−19)−129(31−12)}{57(198−128)}\)
\(=\frac {228(198−128)}{57(198−128)}\)
\(= \frac {228}{57}\)
\(=4\)
So, the answer is \(4\).
A geometric progression is the sequence, in which each term is varied by another by a common ratio. The next term of the sequence is produced when we multiply a constant to the previous term. It is represented by: a, ar1, ar2, ar3, ar4, and so on.
Important properties of GP are as follows:
If a1, a2, a3,… is a GP of positive terms then log a1, log a2, log a3,… is an AP (arithmetic progression) and vice versa