Given, \(α_n = 19^n – 12^n\)
Let equation of roots \(12\) & \(19\) i.e.
\(x^2−31x+228=0\)
Where, \(x = 19\) or \(12\)
Thus,
\(\frac {31α_9−α_{10}}{57α_8}=\frac {31(199−129)−(1910−1210)}{57(198−128)}\)
\(=\frac {199(31−19)−129(31−12)}{57(198−128)}\)
\(=\frac {228(198−128)}{57(198−128)}\)
\(= \frac {228}{57}\)
\(=4\)
So, the answer is \(4\).
The equivalent resistance between the points \(A\) and \(B\) in the given circuit is \[ \frac{x}{5}\,\Omega. \] Find the value of \(x\). 
Method used for separation of mixture of products (B and C) obtained in the following reaction is: 
In the following \(p\text{–}V\) diagram, the equation of state along the curved path is given by \[ (V-2)^2 = 4ap, \] where \(a\) is a constant. The total work done in the closed path is: 
Let \( ABC \) be a triangle. Consider four points \( p_1, p_2, p_3, p_4 \) on the side \( AB \), five points \( p_5, p_6, p_7, p_8, p_9 \) on the side \( BC \), and four points \( p_{10}, p_{11}, p_{12}, p_{13} \) on the side \( AC \). None of these points is a vertex of the triangle \( ABC \). Then the total number of pentagons that can be formed by taking all the vertices from the points \( p_1, p_2, \ldots, p_{13} \) is ___________.
A geometric progression is the sequence, in which each term is varied by another by a common ratio. The next term of the sequence is produced when we multiply a constant to the previous term. It is represented by: a, ar1, ar2, ar3, ar4, and so on.
Important properties of GP are as follows:
If a1, a2, a3,… is a GP of positive terms then log a1, log a2, log a3,… is an AP (arithmetic progression) and vice versa