A → Products
For a first order reaction,
\(t_{1/2} = \frac{ln2}{k} = \frac{0.693 }{ k}\)
Time for \(90\% \) conversion,
\(t_{ 90\%} = \frac{1}{k} \;In \;\frac{100}{10 }= \frac{ln10}{k} = \frac{2.303}{k}\)
\(t_{90\%} = \frac{2.303}{0.693} \;t_{1/2} = 3.32 \;t_{1/2}\)
The following data were obtained for the reaction: \[ 2NO(g) + O_2(g) \rightarrow 2N_2O(g) \] at different concentrations:
The rate law of this reaction is:
20 mL of sodium iodide solution gave 4.74 g silver iodide when treated with excess of silver nitrate solution. The molarity of the sodium iodide solution is _____ M. (Nearest Integer value) (Given : Na = 23, I = 127, Ag = 108, N = 14, O = 16 g mol$^{-1}$)
The Order of reaction refers to the relationship between the rate of a chemical reaction and the concentration of the species taking part in it. In order to obtain the reaction order, the rate equation of the reaction will given in the question.