For a chemical reaction A → B, the rate doubles when the concentration of A is increased four times. The order of reaction is
Rate ∠[A]â¿: solve for n.
2
1
1/2
Zero
2 = 4⿠→ n = 1/2, so order is 1/2.
The following data were obtained during the first order thermal decomposition of \( \text{N}_2\text{O}_5(g) \) at constant volume: