Following chromatogram was developed by adsorption of compound 'A' on a 6 cm TLC glass plate. Retardation factor of the compound 'A' is_____ \(\times 10^{–1}\).
For Rf calculations:
• Measure the distances accurately for the solute and solvent front.
• Ensure the units for both distances are consistent.
• Multiply the calculated Rf value by 10−1 if required.
1. Retardation Factor (\(R_f\)):
The \(R_f\) value is defined as:
\[R_f = \frac{\text{Distance traveled by the solute (A)}}{\text{Distance traveled by the solvent front}}.\]
2. Given Data:
Total length of the TLC plate = 6 cm.
Let the solute travel 3.6 cm and the solvent front travel 6 cm.
3. Calculate \(R_f\):
\[R_f = \frac{3.6}{6} = 0.6.\]
4.Convert to \(10^{-1}\) Factor:
\[R_f \times 10^{-1} = 6 \times 10^{-1}.\]
Final Answer: \(0.6\).
Let a line passing through the point $ (4,1,0) $ intersect the line $ L_1: \frac{x - 1}{2} = \frac{y - 2}{3} = \frac{z - 3}{4} $ at the point $ A(\alpha, \beta, \gamma) $ and the line $ L_2: x - 6 = y = -z + 4 $ at the point $ B(a, b, c) $. Then $ \begin{vmatrix} 1 & 0 & 1 \\ \alpha & \beta & \gamma \\ a & b & c \end{vmatrix} \text{ is equal to} $
Resonance in X$_2$Y can be represented as
The enthalpy of formation of X$_2$Y is 80 kJ mol$^{-1}$, and the magnitude of resonance energy of X$_2$Y is: