Following chromatogram was developed by adsorption of compound 'A' on a 6 cm TLC glass plate. Retardation factor of the compound 'A' is_____ \(\times 10^{–1}\).
For Rf calculations:
• Measure the distances accurately for the solute and solvent front.
• Ensure the units for both distances are consistent.
• Multiply the calculated Rf value by 10−1 if required.
1. Retardation Factor (\(R_f\)):
The \(R_f\) value is defined as:
\[R_f = \frac{\text{Distance traveled by the solute (A)}}{\text{Distance traveled by the solvent front}}.\]
2. Given Data:
Total length of the TLC plate = 6 cm.
Let the solute travel 3.6 cm and the solvent front travel 6 cm.
3. Calculate \(R_f\):
\[R_f = \frac{3.6}{6} = 0.6.\]
4.Convert to \(10^{-1}\) Factor:
\[R_f \times 10^{-1} = 6 \times 10^{-1}.\]
Final Answer: \(0.6\).
If all the words with or without meaning made using all the letters of the word "KANPUR" are arranged as in a dictionary, then the word at 440th position in this arrangement is:
If the system of equations \[ x + 2y - 3z = 2, \quad 2x + \lambda y + 5z = 5, \quad 14x + 3y + \mu z = 33 \] has infinitely many solutions, then \( \lambda + \mu \) is equal to:}
The equilibrium constant for decomposition of $ H_2O $ (g) $ H_2O(g) \rightleftharpoons H_2(g) + \frac{1}{2} O_2(g) \quad (\Delta G^\circ = 92.34 \, \text{kJ mol}^{-1}) $ is $ 8.0 \times 10^{-3} $ at 2300 K and total pressure at equilibrium is 1 bar. Under this condition, the degree of dissociation ($ \alpha $) of water is _____ $\times 10^{-2}$ (nearest integer value). [Assume $ \alpha $ is negligible with respect to 1]