Question:
Find the probability of 53 Sundays in a leap year.
Find the probability of 53 Sundays in a leap year.
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A leap year has 52 complete weeks and 2 extra days. If one of those extra days is Sunday, the year has 53 Sundays.
Updated On: Feb 27, 2025
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Solution and Explanation
Step 1: Identify total Sundays in a leap year. A leap year has 366 days, which means 52 complete weeks + 2 extra days.
Step 2: Determine favorable cases. The extra 2 days can be: \begin{itemize} \item - (Sunday, Monday) \item - (Monday, Tuesday) \item - (Tuesday, Wednesday) \item - (Wednesday, Thursday) \item - (Thursday, Friday) \item - (Friday, Saturday) \item - (Saturday, Sunday) \end{itemize} In 2 out of 7 cases, Sunday is included.
Step 3: Compute probability. \[ P(\text{53 Sundays}) = \frac{2}{7} \]
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