Question:
Find the order of the differential equation
\[
\frac{d^3y}{dx^3} + x^2 \left(\frac{d^2y}{dx^2}\right)^3 + \frac{dy}{dx} + y = 0.
\]
Find the order of the differential equation
\[
\frac{d^3y}{dx^3} + x^2 \left(\frac{d^2y}{dx^2}\right)^3 + \frac{dy}{dx} + y = 0.
\]
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The order of a differential equation is determined by the highest derivative appearing in the equation.
Updated On: Mar 1, 2025
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Solution and Explanation
The order of a differential equation is the highest derivative present in the equation. In this case, the highest derivative is \( \frac{d^3y}{dx^3} \), which is of order 3.
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