
For mutual inductance in coplanar loops:
• Use the magnetic field from the larger loop and calculate flux through the smaller loop.
• Divide flux by the current to obtain mutual inductance.
\(M = \frac{\sqrt{2} \mu_0 R^2}{L}\)
\(M = \frac{2 \sqrt{2} \mu_0 R}{L^2}\)
\(M = \frac{2 \sqrt{2} \mu_0 R^2}{L}\)
\(M = \frac{\sqrt{2} \mu_0 R}{L^2}\)
\[ \phi = M i \]
\[ \phi = (BA) \]
\[ \phi = \pi R^2 \left( \frac{4\mu_0}{4\pi} \cdot i \cdot \frac{L}{2} \right) \sqrt{2} \]
\[ \implies M = \frac{2\sqrt{2} \mu_0 R^2}{L} \]
Let A be a 3 × 3 matrix such that \(\text{det}(A) = 5\). If \(\text{det}(3 \, \text{adj}(2A)) = 2^{\alpha \cdot 3^{\beta} \cdot 5^{\gamma}}\), then \( (\alpha + \beta + \gamma) \) is equal to:
