For mutual inductance in coplanar loops:
• Use the magnetic field from the larger loop and calculate flux through the smaller loop.
• Divide flux by the current to obtain mutual inductance.
\(M = \frac{\sqrt{2} \mu_0 R^2}{L}\)
\(M = \frac{2 \sqrt{2} \mu_0 R}{L^2}\)
\(M = \frac{2 \sqrt{2} \mu_0 R^2}{L}\)
\(M = \frac{\sqrt{2} \mu_0 R}{L^2}\)
\[ \phi = M i \]
\[ \phi = (BA) \]
\[ \phi = \pi R^2 \left( \frac{4\mu_0}{4\pi} \cdot i \cdot \frac{L}{2} \right) \sqrt{2} \]
\[ \implies M = \frac{2\sqrt{2} \mu_0 R^2}{L} \]
Electrolysis of 600 mL aqueous solution of NaCl for 5 min changes the pH of the solution to 12. The current in Amperes used for the given electrolysis is ….. (Nearest integer).
If the system of equations \[ x + 2y - 3z = 2, \quad 2x + \lambda y + 5z = 5, \quad 14x + 3y + \mu z = 33 \] has infinitely many solutions, then \( \lambda + \mu \) is equal to:}