Question

If an inductor coil of self-inductance 2H stores 25J of magnetic energy, then the current passing through it is:

• A. 10A
• B. 5A
• C. 7A
• D. 12A

Hint:

To find the current passing through an inductor, use the formula for the energy stored in the inductor: \( E = \frac{1}{2} L I^2 \).

Answer 1

The Correct Option is B

The energy \( E \) stored in an inductor is given by the formula: \[ E = \frac{1}{2} L I^2 \] where \( L \) is the inductance and \( I \) is the current. We are given \( E = 25 \, \text{J} \) and \( L = 2 \, \text{H} \), and we need to find \( I \). Substituting the values: \[ 25 = \frac{1}{2} \times 2 \times I^2 \] Simplifying: \[ 25 = I^2 \] Taking the square root of both sides: \[ I = 5 \, \text{A} \]
Thus, the current passing through the inductor is \( 5 \, \text{A} \).