Find the mean deviation about the mean for the data
\(x_i\) | 10 | 30 | 50 | 70 | 90 |
\(f_i\) | 4 | 24 | 28 | 16 | 8 |
\(x_i\) | \(f_i\) | \(f_ix_i\) | \(|x_i-\bar{x}|\) | \(f_i|x_i-\bar{x}|\) |
10 | 4 | 40 | 40 | 160 |
30 | 24 | 720 | 20 | 480 |
50 | 28 | 1400 | 0 | 0 |
70 | 16 | 1120 | 20 | 320 |
90 | 8 | 720 | 40 | 320 |
80 | 4000 | 1280 |
\(N=\sum_{I=1}^{5}f_i=80\) \(\sum_{I=1}^{5}f_i=4000\)
∴ \(\bar{x}=\frac{1}{N}\sum_{I=1}^{5}f_ix_i=\frac{1}{80}X4000=50\)
\(MD(\bar{x})=\frac{1}{N}\sum_{i=1}^{5}f_i|x_i-\bar{x}|=\frac{1}{80}×1280= 16\)
xi | 2 | 4 | 6 | 8 | 10 | 12 | 14 | 16 |
fi | 4 | 4 | α | 15 | 8 | β | 4 | 5 |
The mean deviation about the median for the data 3, 5, 9,3, 8, 10, 7 is
Figures 9.20(a) and (b) refer to the steady flow of a (non-viscous) liquid. Which of the two figures is incorrect ? Why ?
A statistical measure that is used to calculate the average deviation from the mean value of the given data set is called the mean deviation.
The mean deviation for the given data set is calculated as:
Mean Deviation = [Σ |X – µ|]/N
Where,
Grouping of data is very much possible in two ways: