The given quadratic equation is:
\[
2x^2 - 4x + 3 = 0.
\]
The discriminant \( \Delta \) of a quadratic equation \( ax^2 + bx + c = 0 \) is given by:
\[
\Delta = b^2 - 4ac.
\]
For the equation \( 2x^2 - 4x + 3 = 0 \), we have \( a = 2 \), \( b = -4 \), and \( c = 3 \). Substituting these values into the discriminant formula:
\[
\Delta = (-4)^2 - 4(2)(3) = 16 - 24 = -8.
\]
Since the discriminant is negative (\( \Delta = -8 \)), the roots of the quadratic equation are imaginary.
Conclusion:
The discriminant of the quadratic equation is \( -8 \), and hence the roots are imaginary.