For \( X = (x_1, x_2, x_3)^T \in \mathbb{R}^3 \), consider the quadratic form:
\[ Q(X) = 2x_1^2 + 2x_2^2 + 3x_3^2 + 4x_1x_2 + 2x_1x_3 + 2x_2x_3. \] Let \( M \) be the symmetric matrix associated with the quadratic form \( Q(X) \) with respect to the standard basis of \( \mathbb{R}^3 \).
Let \( Y = (y_1, y_2, y_3)^T \in \mathbb{R}^3 \) be a non-zero vector, and let
\[ a_n = \frac{Y^T(M + I_3)^{n+1}Y}{Y^T(M + I_3)^n Y}, \quad n = 1, 2, 3, \dots \] Then, the value of \( \lim_{n \to \infty} a_n \) is equal to (in integer).
Step 1: Matrix Representation
The quadratic form \( Q(X) \) can be written in matrix form as:
\[ Q(X) = X^T M X, \] where \( M \) is the symmetric matrix associated with the quadratic form. We need to compute the matrix \( M \) and the limit of the sequence defined by \( a_n \).
Step 2: Matrix Computation
We compute the matrix \( M \) corresponding to the quadratic form. The matrix \( M \) will be a symmetric matrix with entries corresponding to the coefficients of the quadratic form \( Q(X) \). \[ M = \begin{pmatrix} 2 & 2 & 1 \\ 2 & 2 & 1 \\ 1 & 1 & 3 \end{pmatrix}. \] Step 3: Analyzing the Limit
The expression for \( a_n \) involves powers of the matrix \( M + I_3 \), where \( I_3 \) is the identity matrix. As \( n \to \infty \), the powers of \( M + I_3 \) will be dominated by its largest eigenvalue. Therefore, the ratio \( a_n \) will approach the largest eigenvalue of the matrix \( M + I_3 \). The largest eigenvalue of \( M + I_3 \) is \( 6 \).
Step 4: Conclusion
Thus, \( \lim_{n \to \infty} a_n = 6 \).
\[ \boxed{6} \quad \lim_{n \to \infty} a_n = 6 \]
A square paper, shown in figure (I), is folded along the dotted lines as shown in figures (II) and (III). Then a few cuts are made as shown in figure (IV). Which one of the following patterns will be obtained when the paper is unfolded?
In the diagram, the lines QR and ST are parallel to each other. The shortest distance between these two lines is half the shortest distance between the point P and the line QR. What is the ratio of the area of the triangle PST to the area of the trapezium SQRT?
Note: The figure shown is representative