Find the area between the curves y=x and y=x2
The required area is represented by the shaded area OBAO as
The points of intersection of the curves,y=x and y=x2,is A(1,1).
We draw AC perpendicular to x-axis.
∴Area(OBAO)=Area(ΔOCA)-Area(OCABO)...(1)
=
\[\int_{0}^{1} x \,dx\]-
\[-\int_{0}^{1} x^2 \,dx\]
=[\(\frac{x^2}{2}\)]10-[\(\frac{x^3}{3}\)]10
=\(\frac{1}{2}\)-\(\frac{1}{3}\)
=\(\frac 16\)units
Bittu and Chintu were partners in a firm sharing profit and losses in the ratio of 4 : 3. Their Balance Sheet as at 31st March, 2024 was as follows:
On 1st April, 2024, Diya was admitted in the firm for \( \frac{1}{7} \)th share in the profits on the following terms:
Prepare Revaluation Account and Partners' Capital Accounts.