Find the area between the curves y=x and y=x2
The required area is represented by the shaded area OBAO as
The points of intersection of the curves,y=x and y=x2,is A(1,1).
We draw AC perpendicular to x-axis.
∴Area(OBAO)=Area(ΔOCA)-Area(OCABO)...(1)
=
\[\int_{0}^{1} x \,dx\]-
\[-\int_{0}^{1} x^2 \,dx\]
=[\(\frac{x^2}{2}\)]10-[\(\frac{x^3}{3}\)]10
=\(\frac{1}{2}\)-\(\frac{1}{3}\)
=\(\frac 16\)units
If 5f(x) + 4f (\(\frac{1}{x}\)) = \(\frac{1}{x}\)+ 3, then \(18\int_{1}^{2}\) f(x)dx is: