Evaluate\(\begin{vmatrix} x &y &x+y \\ y&x+y &x \\ x+y&x &y \end{vmatrix}\)
\(\Delta = \begin{vmatrix} x &y &x+y \\ y&x+y &x \\ x+y&x &y \end{vmatrix}\)
Applying R1\(\rightarrow\)R1+R2+R3, we have
Δ=\(\begin{vmatrix} 2(x+y) &y &x+y \\ 2(x+y)&x+y &x \\ 2(x+y)&x &y \end{vmatrix}\)
= 2(x+y)\(\begin{vmatrix} 1&y &x+y \\ 1&x+y &x \\ 1&x &y \end{vmatrix}\)
Applying C2\(\rightarrow\)C2-C1 and C3\(\rightarrow\)C3-C1, we have
Δ=2(x+y)\(\begin{vmatrix} 1 &y &x+y \\ 0&x &x \\ 0&x-y & -x \end{vmatrix}\)
Expanding along R1, we have:
Δ=2(x+y)[-x2+y(x-y)]
=-2(x+y)(x2+y2-yx)
=-2(x3+y3)
If \(\begin{vmatrix} 2x & 3 \\ x & -8 \\ \end{vmatrix} = 0\), then the value of \(x\) is:
Draw a rough sketch for the curve $y = 2 + |x + 1|$. Using integration, find the area of the region bounded by the curve $y = 2 + |x + 1|$, $x = -4$, $x = 3$, and $y = 0$.
A school is organizing a debate competition with participants as speakers and judges. $ S = \{S_1, S_2, S_3, S_4\} $ where $ S = \{S_1, S_2, S_3, S_4\} $ represents the set of speakers. The judges are represented by the set: $ J = \{J_1, J_2, J_3\} $ where $ J = \{J_1, J_2, J_3\} $ represents the set of judges. Each speaker can be assigned only one judge. Let $ R $ be a relation from set $ S $ to $ J $ defined as: $ R = \{(x, y) : \text{speaker } x \text{ is judged by judge } y, x \in S, y \in J\} $.