Question:

Evaluate \(\begin{vmatrix} cos\alpha cos\beta &cos\alpha sin\beta  &-sin\alpha \\   -sin\beta&cos\beta  &0 \\   sin\alpha cos\beta&sin\alpha\sin\beta  &cos\alpha  \end{vmatrix}\)

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Solution and Explanation

\(\Delta = \begin{vmatrix} cos\alpha cos\beta &cos\alpha sin\beta  &-sin\alpha \\   -sin\beta&cos\beta  &0 \\   sin\alpha cos\beta&sin\alpha\sin\beta  &cos\alpha  \end{vmatrix}\)

Expanding along C3, we have: 
Δ=-sinα(-sinαsin2β-cos2βsinα)+cosα(cosαcos2β+cosαsin2β)
=sin2α(sin2β+cos2β)+cos2α(cos2β+sin2β)
=sin2α(1)+cos2α(1)
=1

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