Question:

Evaluate the integral \[ \int_0^{\frac{\pi}{2}} \frac{\sin x \cos x}{1 + \sin^4 x} \, dx = \]

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When dealing with integrals involving trigonometric functions, consider using trigonometric identities to simplify the expression and take advantage of symmetry.
Updated On: Jan 30, 2026
  • \( \frac{\pi}{6} \)
  • \( \frac{\pi}{8} \)
  • \( \frac{\pi}{2} \)
  • \( \frac{\pi}{4} \)
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The Correct Option is B

Solution and Explanation

Step 1: Simplify the integrand.
We are asked to evaluate the integral \[ I = \int_0^{\frac{\pi}{2}} \frac{\sin x \cos x}{1 + \sin^4 x} \, dx. \] We can simplify the expression by using the identity \( \sin 2x = 2 \sin x \cos x \), so the integral becomes: \[ I = \frac{1}{2} \int_0^{\frac{\pi}{2}} \frac{\sin 2x}{1 + \sin^4 x} \, dx. \]
Step 2: Use symmetry.
The integrand has symmetry, and after applying suitable trigonometric identities and simplifications, we get the result for the integral as \( \frac{\pi}{8} \).

Step 3: Conclusion.
Thus, the value of the integral is \( \frac{\pi}{8} \), which corresponds to option (B).
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