Step 1: Decompose the integrand using partial fractions. First, express the rational function as: \[ \frac{x^2 + x + 1}{(x + 2)(x^2 + 1)} = \frac{A}{x + 2} + \frac{Bx + C}{x^2 + 1} \]
Step 2: Multiply both sides by \( (x + 2)(x^2 + 1) \) to find the values of \( A \), \( B \), and \( C \).
Step 3: Solve for \( A \), \( B \), and \( C \) by equating coefficients of like powers of \( x \).
Step 4: Once the partial fraction decomposition is done, integrate each term separately. After integrating, the result is: \[ \int \frac{x^2 + x + 1}{(x + 2)(x^2 + 1)} \, dx = \ln |x + 2| + \frac{1}{2} \ln (x^2 + 1) + C. \]
Find the value of \[ \int \frac{\sec^2 2x}{(\cot x - \tan x)^2} \, dx. \]
Prove that \[ \int_0^{\pi} \frac{x \tan x}{\sec x + \tan x} \, dx = \frac{\pi}{2} (\pi - 2). \]
Find the value of \[ \int e^x \left( \tan^{-1} x + \frac{1}{1 + x^2} \right) dx. \]
Integrate \[ \int \frac{\sin(\tan^{-1} x)}{1 + x^2} \, dx. \]
A die is thrown two times. It is found that the sum of the appeared numbers is 6. Find the conditional that the number 4 appeared at least one time.
There are two children in a family. If it is known that at least one child is a boy, find the that both children are boys.
Prove that the \( f(x) = x^2 \) is continuous at \( x \neq 0 \).
Differentiate the \( \sin mx \) with respect to \( x \).
The principal value of the \( \cot^{-1}\left(-\frac{1}{\sqrt{3}}\right) \) will be: