This is a standard integral. We know that:
\[
\int_0^{\pi/2} \log(\sin x) \, dx = \int_0^{\pi/2} \log(\cos x) \, dx = -\frac{\pi}{2} \log 2.
\]
Hence,
\[
\int_0^{\pi/2} \log (\cos x) \, dx = -\frac{\pi}{2} \log 2.
\]
Final answer:
\[
\boxed{
\int_0^{\pi/2} \log (\cos x) \, dx = -\frac{\pi}{2} \log 2.
}
\]