(i) {\((\frac{1}{3})^{−1} − (\frac{1}{4})^{−1}\)}−1
\((\frac{a}{b})^{−m} = (\frac{b}{a})^m\)
{\((\frac{1}{3})^{−1} − (\frac{1}{4})^{−1}\)}−1
\(= (3^1 − 4^1)−1\)
\(= (3 − 4)^{−1}\)
\(= (−1)^{−1}\)
\(= (\frac{−1}{1})^1= −1\)
(ii) \((\frac{5}{8})^{−7}× (\frac{8}{5})^{−4} \)
We know that, \((\frac{a}{b})^{−m} = (\frac{b}{a})^m\)
\((\frac{5}{8})^{−7}× (\frac{8}{5})^{−4} \)
\(= (\frac{8}{5})^7 × (\frac{8}{5})^{−4}\)
\(= (\frac{8}{5})^3\) [Since, \(\frac{a^m}{a^n} = a^{m - n}\)]
\(= \frac{512}{125}\)