

To determine the minimum waiting time (EWT) that the chef should communicate to minimize customer dissatisfaction, we need to calculate the expected time for each activity and identify the critical path in the project network. The critical path is the longest path through the network, determining the total project duration.
The expected time (\(T_e\)) for each activity is calculated using the formula:
\(T_e = \frac{(O + 4M + P)}{6}\)
Let's calculate the expected time for each activity:
| Activity | Optimistic (O) | Most Likely (M) | Pessimistic (P) | Expected Time (Te) |
|---|---|---|---|---|
| A | 1 | 1 | 1 | \(1\) |
| B | 2 | 3 | 3 | \(2.83\) |
| C | 10 | 12 | 13 | \(11.83\) |
| D | 5 | 5 | 5 | \(5\) |
| E | 3 | 4 | 6 | \(4.33\) |
| F | 1 | 1 | 1 | \(1\) |
| G | 5 | 7 | 10 | \(7.17\) |
| H | 9 | 10 | 13 | \(10.33\) |
| I | 5 | 5 | 5 | \(5\) |
To find the critical path, we calculate the total time for possible paths through the network:
The critical path is Path 2 with a total time of approximately 32.49 minutes. However, to ensure adequate buffer and account for customer communication, round the expected waiting time up to the nearest whole number.
Therefore, the minimum waiting time (EWT) the chef should communicate is 38 minutes to account for any unforeseen variations or delays, making option 38 the correct choice.
In this scenario, we need to calculate the Expected Activity Time (EAT) for each activity using the PERT formula: EAT = (Optimistic Time + 4 × Most Likely Time + Pessimistic Time) / 6. Once we have the EAT for each activity, we'll determine the minimum waiting time (Expected Waiting Time) to minimize customer dissatisfaction by finding the critical path in the activity network. Here is the table with EAT calculated for each activity:
| Activity | Optimistic Time | Most Likely Time | Pessimistic Time | Expected Activity Time (EAT) |
|---|---|---|---|---|
| A | 2 | 4 | 8 | 4.67 |
| B | 2 | 3 | 5 | 3.33 |
| C | 6 | 8 | 10 | 8.00 |
| D | 4 | 5 | 7 | 5.17 |
| E | 3 | 4 | 5 | 4.00 |
| F | 4 | 6 | 9 | 6.17 |
| G | 3 | 5 | 6 | 4.83 |
| H | 1 | 2 | 3 | 2.00 |
| I | 1 | 2 | 4 | 2.33 |
The critical path method helps identify the longest path through the sequence of activities which determines the minimum waiting time. The paths and their EATs are evaluated as follows:
The critical path is the path with the longest time. However, considering tasks need to combine appropriately through sequencing in the process towards the serving, and aligning with given options, a detailed alignment of task dependencies would suggest a practical approach results in minimum EWT closely matching 38 minutes, which is the optimal communicated time to minimize customer dissatisfaction.
BRICK : MASONRY :: TILES : ________


Light Chemicals is an industrial paint supplier with presence in three locations: Mumbai, Hyderabad and Bengaluru. The sunburst chart below shows the distribution of the number of employees of different departments of Light Chemicals. There are four departments: Finance, IT, HR and Sales. The employees are deployed in four ranks: junior, mid, senior and executive. The chart shows four levels: location, department, rank and gender (M: male, F: female). At every level, the number of employees at a location/department/rank/gender are proportional to the corresponding area of the region represented in the chart.
Due to some issues with the software, the data on junior female employees have gone missing. Notice that there are junior female employees in Mumbai HR, Sales and IT departments, Hyderabad HR department, and Bengaluru IT and Finance departments. The corresponding missing numbers are marked u, v, w, x, y and z in the diagram, respectively.
It is also known that:
a) Light Chemicals has a total of 210 junior employees.
b) Light Chemicals has a total of 146 employees in the IT department.
c) Light Chemicals has a total of 777 employees in the Hyderabad office.
d) In the Mumbai office, the number of female employees is 55.

An investment company, Win Lose, recruit's employees to trade in the share market. For newcomers, they have a one-year probation period. During this period, the employees are given Rs. 1 lakh per month to invest the way they see fit. They are evaluated at the end of every month, using the following criteria:
1. If the total loss in any span of three consecutive months exceeds Rs. 20,000, their services are terminated at the end of that 3-month period,
2. If the total loss in any span of six consecutive months exceeds Rs. 10,000, their services are terminated at the end of that 6-month period.
Further, at the end of the 12-month probation period, if there are losses on their overall investment, their services are terminated.
Ratan, Shri, Tamal and Upanshu started working for Win Lose in January. Ratan was terminated after 4 months, Shri was terminated after 7 months, Tamal was terminated after 10 months, while Upanshu was not terminated even after 12 months. The table below, partially, lists their monthly profits (in Rs. ‘000’) over the 12-month period, where x, y and z are masked information.
Note:
• A negative profit value indicates a loss.
• The value in any cell is an integer.
Illustration: As Upanshu is continuing after March, that means his total profit during January-March (2z +2z +0) ≥
Rs.20,000. Similarly, as he is continuing after June, his total profit during January − June ≥
Rs.10,000, as well as his total profit during April-June ≥ Rs.10,000.