Question

Dipped in the solution, the electrode exchanges charges with the electrolyte. The positive electrode develops a potential \( V_+ \) (\( V_+>0 \)), and the negative electrode develops a potential \(-V_-\) (\( V_- \geq 0 \)), relative to the electrolyte adjacent to it. When no current is drawn from the cell, then:

Answer 1

The electromotive force (emf) of the cell is given by the sum of the potential differences between the positive and negative electrodes relative to the electrolyte. Since both V+ and V− are positive, their sum is also positive, making option (A) correct.