Question

Current passing through a wire as function of time is given as $I(t)=0.02 \mathrm{t}+0.01 \mathrm{~A}$. The charge that will flow through the wire from $t=1 \mathrm{~s}$ to $\mathrm{t}=2 \mathrm{~s}$ is:

• A. 0.06 C
• B. 0.02 C
• C. 0.07 C
• D. 0.04 C

Hint:

Integrate the current function to find the charge.

Answer 1

The Correct Option is D

1. Charge calculation: \[ q = \int I(t) dt \] \[ q = \int_{1}^{2} (0.02t + 0.01) dt \] \[ q = \left[ 0.02 \frac{t^2}{2} + 0.01t \right]_{1}^{2} \] \[ q = \left[ 0.01(4) + 0.01(2) \right] - \left[ 0.01(1) + 0.01(1) \right] \] \[ q = 0.04 \mathrm{~C} \] Therefore, the correct answer is (4) 0.04 C.