Question:
Correct order of stability of carbanion is
Correct order of stability of carbanion is
Updated On: Nov 24, 2024
- c > b > d > a
- a > b > c > d
- d > a > c > b
- d > c > b > a
Hide Solution
Verified By Collegedunia
The Correct Option is D
Solution and Explanation
Among the given compounds, compound (d) is aromatic, which greatly enhances its stability due to resonance stabilization. Compound (a) is antiaromatic, making it the least stable among the given options.
Compound(b) and compound (c) have sp3 hybridized carbon atoms bearing the negative charge. Based on angle strain theory, compound (c) is more stable than compound (b) due to its ring structure.
Was this answer helpful?
0
0
Top Questions on Organic Reactions
- JEE Main - 2024
- Chemistry
- Organic Reactions
- 9.3 g of pure aniline upon diazotisation followed by coupling with phenol gives an orange dye. The mass of orange dye produced (assume 100% yield/ conversion) is ________g. (nearest integer)
- JEE Main - 2024
- Chemistry
- Organic Reactions
- The major product of the following reaction is P.
- JEE Main - 2024
- Chemistry
- Organic Reactions
- From 6.55 g of aniline, the maximum amount of acetanilide that can be prepared will be ___ × \( 10^{-1} \) g.
- JEE Main - 2024
- Chemistry
- Organic Reactions
- JEE Main - 2024
- Chemistry
- Organic Reactions
Questions Asked in JEE Main exam
- Two bodies of mass 4 g and 25 g are moving with equal kinetic energies. The ratio of the magnitude of their linear momentum is:
- JEE Main - 2024
- Kinetic Energy
- A bullet is fired into a fixed target looses one third of its velocity after travelling 4 cm. It penetrates further \( D \times 10^{-3} \) m before coming to rest. The value of \( D \) is :
- JEE Main - 2024
- Newtons Laws of Motion
- The magnetic field existing in a region is given by \[\vec{B} = 0.2(1 + 2x)\hat{k} \, \text{T}.\]A square loop of edge \( 50 \, \text{cm} \) carrying \( 0.5 \, \text{A} \) current is placed in the \( x \)-\( y \) plane with its edges parallel to the \( x \)- and \( y \)-axes, as shown in the figure. The magnitude of the net magnetic force experienced by the loop is ______ \( \text{mN} \).
- JEE Main - 2024
- Moving charges and magnetism
- A simple harmonic oscillator has an amplitude \( A \) and a time period of \( 6\pi \) seconds. Assuming the oscillation starts from its mean position, the time required by it to travel from \( x = A \) to \( x = \frac{\sqrt{3}}{2} A \) will be \( \frac{\pi}{x} \) seconds, where \( x = \, \underline{\hspace{2cm}} \).
- JEE Main - 2024
- Oscillations
- If\(\alpha,-\frac{\pi}{2}<\alpha<\frac{\pi}{2}\)is the solution of\( 4cos\theta+ 5sin\theta=1\)then the value of \(tan\alpha\) is
- JEE Main - 2024
- Trigonometric Equations
View More Questions