Consider two sets A and B. Set A has 5 elements whose mean & variance are 5 and 8 respectively. Set B has also 5 elements whose mean & variance are 12 & 20 respectively. A new set C is formed by subtracting 3 from each element of set A and by adding 2 to each element of set B. The sum of mean & variance of the set C is
The correct answer is : 58
\(\bar{X_c}=\) mean of c = \(\frac{(5-3)+(12+2)}{2}=8\)
\(\sigma^2_{12}\)=variance of c
\(= \frac{n_1(\sigma_1^2-d_1^2)+n_1(\sigma_2^2+d_2^2)}{n_1+n_2}\)
\(d_1=\bar{x_{12}-\bar{x_1}}\)
\(d_2=\bar{x_{12}-\bar{x_2}}\)
\(n_1=5,\sigma_1^2=8,d_1=8-2=6\)
\(n_2=5,\sigma_2^2=20,d_2=8-14=-6\)
\(\sigma^2_{12}=\frac{5(8+36)+5(20+36)}{10}=50\)
\(\sigma^2_{12}+\bar{x_c}=50+8=58\)
Let \[ A = \{x : |x^2 - 10| \le 6\} \quad \text{and} \quad B = \{x : |x - 2| > 1\}. \] Then
In the given figure, the blocks $A$, $B$ and $C$ weigh $4\,\text{kg}$, $6\,\text{kg}$ and $8\,\text{kg}$ respectively. The coefficient of sliding friction between any two surfaces is $0.5$. The force $\vec{F}$ required to slide the block $C$ with constant speed is ___ N.
(Given: $g = 10\,\text{m s}^{-2}$) 
Two circular discs of radius \(10\) cm each are joined at their centres by a rod, as shown in the figure. The length of the rod is \(30\) cm and its mass is \(600\) g. The mass of each disc is also \(600\) g. If the applied torque between the two discs is \(43\times10^{-7}\) dyne·cm, then the angular acceleration of the system about the given axis \(AB\) is ________ rad s\(^{-2}\).

In mathematics, a set is a well-defined collection of objects. Sets are named and demonstrated using capital letter. In the set theory, the elements that a set comprises can be any sort of thing: people, numbers, letters of the alphabet, shapes, variables, etc.
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The items existing in a set are commonly known to be either elements or members of a set. The elements of a set are bounded in curly brackets separated by commas.
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The cardinal number, cardinality, or order of a set indicates the total number of elements in the set.
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