Question:

Consider two sets A and B. Set A has 5 elements whose mean & variance are 5 and 8 respectively. Set B has also 5 elements whose mean & variance are 12 & 20 respectively. A new set C is formed by subtracting 3 from each element of set A and by adding 2 to each element of set B. The sum of mean & variance of the set C is

Updated On: Apr 6, 2024
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Solution and Explanation

The correct answer is : 58

\(\bar{X_c}=\) mean of c = \(\frac{(5-3)+(12+2)}{2}=8\)

\(\sigma^2_{12}\)=variance of c

\(= \frac{n_1(\sigma_1^2-d_1^2)+n_1(\sigma_2^2+d_2^2)}{n_1+n_2}\)

\(d_1=\bar{x_{12}-\bar{x_1}}\)

\(d_2=\bar{x_{12}-\bar{x_2}}\)

\(n_1=5,\sigma_1^2=8,d_1=8-2=6\)

\(n_2=5,\sigma_2^2=20,d_2=8-14=-6\)

\(\sigma^2_{12}=\frac{5(8+36)+5(20+36)}{10}=50\)

\(\sigma^2_{12}+\bar{x_c}=50+8=58\)

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Concepts Used:

Sets

In mathematics, a set is a well-defined collection of objects. Sets are named and demonstrated using capital letter. In the set theory, the elements that a set comprises can be any sort of thing: people, numbers, letters of the alphabet, shapes, variables, etc.

Read More: Set Theory

Elements of a Set:

The items existing in a set are commonly known to be either elements or members of a set. The elements of a set are bounded in curly brackets separated by commas.

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Cardinal Number of a Set:

The cardinal number, cardinality, or order of a set indicates the total number of elements in the set.

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