For \( Z = 24 \), the electron configuration is \( [Ar] 3d^6 4s^2 \).
- \( l = 1 \) corresponds to the p-orbital, which can hold 6 electrons.
- \( l = 2 \) corresponds to the d-orbital, which can hold 10 electrons.
Thus, there are 12 electrons in the \( l = 1 \) shell and 5 electrons in the \( l = 2 \) shell.
Therefore, the correct answer is (3).
Match the following:
Which of the following is the correct electronic configuration for \( \text{Oxygen (O)} \)?
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is: