Question:
Consider the ground state of an atom (Z = 24). How many electrons are arranged with Azimuthal quantum number $ l = 1 $ and $ l = 2 $ respectively?
Consider the ground state of an atom (Z = 24). How many electrons are arranged with Azimuthal quantum number $ l = 1 $ and $ l = 2 $ respectively?
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The number of electrons in orbitals depends on the quantum numbers, with the \( p \)-orbitals having a maximum of 6 electrons and \( d \)-orbitals having a maximum of 10.
Updated On: Apr 23, 2025
- 12 and 4
- 16 and 4
- 12 and 5
- 12 and 5 and 6
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The Correct Option is C
Solution and Explanation
For \( Z = 24 \), the electron configuration is \( [Ar] 3d^6 4s^2 \).
- \( l = 1 \) corresponds to the p-orbital, which can hold 6 electrons.
- \( l = 2 \) corresponds to the d-orbital, which can hold 10 electrons.
Thus, there are 12 electrons in the \( l = 1 \) shell and 5 electrons in the \( l = 2 \) shell.
Therefore, the correct answer is (3).
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