
The reaction shown is an ozonolysis of 2-butene. The ozone (O3) cleaves the double bond, and the reduction with Zn/H2O results in the formation of aldehydes or ketones. For 2-butene, the ozonolysis reaction can be depicted as:
Reactant: \[\text{CH}_{3}\text{CH}=\text{CH}\text{CH}_{3}\]
Step 1: Ozonolysis cleaves the C=C bond.
Step 2: The products are two molecules of acetaldehyde (\[\text{CH}_{3}\text{CHO}\]).
Product (P): Each acetaldehyde molecule contains one oxygen atom.
| Molecule | Oxygen Atoms |
|---|---|
| Acetaldehyde (\[\text{CH}_{3}\text{CHO}\]) | 1 |
Since 2-butene is symmetrical, only one type of product is formed, which is acetaldehyde. The total number of oxygen atoms per molecule of product (P) is therefore 1.
Upon ozonolysis, the compound CH3–CH=CH–CH3 is cleaved at the double bond, resulting in two molecules of CH3–C=O.
Each resulting molecule contains one oxygen atom.
Hence, the total number of oxygen atoms present per molecule of the product is: 1
So, the correct answer is: 1.
Match List-I with List-II: List-I
The correct increasing order of stability of the complexes based on \( \Delta \) value is:

Method used for separation of mixture of products (B and C) obtained in the following reaction is: 