Question

Consider the following sequence of reactions:

i) \( \text{Mg}, \text{dry ether} \)
ii) \( \text{CO}_2, \text{H}_2\text{O}^+ \)
iii) \( \text{NH}_3, \Delta \)

11.25 mg of chlorobenzene will produce \( x \times 10^{-1} \) mg of product B. Given molar mass of C, H, O, N, and Cl as 12, 1, 16, 14, and 35.5 g mol\(^{-1}\), respectively, the value of \( x \) is:

Hint:

Use stoichiometric calculations to find the final mass or amount of a product after a reaction.

Answer 1

Step 1: Determine the moles of chlorobenzene.

\[ \text{Moles of chlorobenzene} = \frac{11.25 \, \text{mg}}{1 \, \text{g/mol}} = \frac{11.25 \times 10^{-3}}{C_6H_5Cl} \]

Step 2: Calculate the corresponding amount of product B after completing the reaction. Final Conclusion: The value of \( x \) is 9.