Question:

Consider the following reaction
\[A + B \rightarrow C\]
The time taken for A to become 1/4th of its initial concentration is twice the time taken to become 1/2 of the same. Also, when the change of concentration of B is plotted against time, the resulting graph gives a straight line with a negative slope and a positive intercept on the concentration axis.
The overall order of the reaction is ____.

Updated On: Nov 24, 2024
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Correct Answer: 1

Solution and Explanation

Order with respect to A
For a first-order reaction:
\[t_{75\%} = 2 \times t_{50\%}.\]
This is consistent with the information given, so the reaction is first order with respect to A.
Order with respect to B The plot of [B] versus $t$ is a straight line, which indicates that the reaction is zero order with respect to B.
Overall order of the reaction:
\[\text{Order} = 1 \, (\text{w.r.t. A}) + 0 \, (\text{w.r.t. B}) = 1.\]
Final Answer:\[1.\]

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