The given equation is:
\[ \int_1^e \frac{(\log_e x)^{1/2}}{x \left( a - (\log_e x)^{3/2} \right)^2} \, dx = 1, \quad a \in (-\infty, 0) \cup (1, \infty) \] We need to determine which of the following statements are TRUE about \( a \).
Let's start by making a substitution to simplify the integral. Let: \[ u = (\log_e x)^{1/2} \] Therefore: \[ u^2 = \log_e x \quad \text{and} \quad x = e^{u^2} \] Now, the differential \( dx \) becomes: \[ dx = 2u e^{u^2} \, du \] With this substitution, the integral transforms into: \[ \int_1^e \frac{u}{e^{u^2} \left( a - u^3 \right)^2} \cdot 2u e^{u^2} \, du = 1 \] Simplifying: \[ \int_0^1 \frac{2u^2}{(a - u^3)^2} \, du = 1 \] This integral now depends on the value of \( a \).
The integral's behavior depends on the choice of \( a \). We are asked to determine which values of \( a \) make the integral equal to 1.
Let's now analyze the given options.
This option is incorrect because there are values of \( a \) that satisfy the equation.
This option is incorrect because no integer values of \( a \) will satisfy the equation.
This is correct. Through analysis, we can find that irrational values of \( a \) satisfy the equation.
This is also correct. There are indeed multiple values of \( a \) that satisfy the equation.
The correct options are: C, D.
Figure 1 shows the configuration of main scale and Vernier scale before measurement. Fig. 2 shows the configuration corresponding to the measurement of diameter $ D $ of a tube. The measured value of $ D $ is:
Definite integral is an operation on functions which approximates the sum of the values (of the function) weighted by the length (or measure) of the intervals for which the function takes that value.
Definite integrals - Important Formulae Handbook
A real valued function being evaluated (integrated) over the closed interval [a, b] is written as :
\(\int_{a}^{b}f(x)dx\)
Definite integrals have a lot of applications. Its main application is that it is used to find out the area under the curve of a function, as shown below: