Question:

Consider an+1 = 1/1+1/an for n = 1,2,.......2008,2009. where a1 = 1. Find the value of a1a2 + a2a3 + a3a4+ .......+ a2008a2009.

Updated On: Aug 9, 2024
  • 2009/1000
  • 2009/2008
  • 2008/2009
  • 6000/2009
  • 2008/6000
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The Correct Option is C

Solution and Explanation

Given that,
a1 = 1
a2 = 1/1+1/1 = 1/2
a3 = 1/1+1/1/2 = 1/1+2 = 1/3
Similarly, a4 = 1/4, a5 = 1/5, .......... a2008 = 1/2008, a2009 = 1/2009
a1a2 + a2a3 + a3a4 + .......... + a2008a2009
= 1x1/2 + 1/2x1/3 + 1/3x1/4 ....... + 1/2008x1/2009
= 2-1/1x2 + 3-2/2x3 + 4-3/3x4 + ......2008-2007/2007x2008 + 2009-2008/2008x2009
= 1-1/2+1/2-1/3+1/3-1/4 .........1/2007-1/2008+1/2008-1/2009
= 1-1/2009
= 2008/2009
Hence, option C is the correct answer.

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