Kirchhoff’s first law (junction rule) states that the sum of currents entering a junction is equal to the sum of currents leaving the junction. This is based on the principle of conservation of charge. Kirchhoff’s second law (loop rule) states that the sum of the potential differences (voltages) around any closed loop is zero. This law is based on the conservation of energy in the circuit. Therefore, the conservation of charge and energy is directly related to Kirchhoff’s junction rule and loop rule.
The correct option is (C) : Kirchhoff's junction rule and loop rule
Kirchhoff's laws are based on fundamental conservation principles:
1. Kirchhoff's Junction Rule:
This rule states that the total current entering a junction equals the total current leaving it.
It is based on the conservation of charge.
2. Kirchhoff's Loop Rule:
This rule states that the total energy gained and lost by a charge around a closed loop is zero.
It is based on the conservation of energy.
Final Answer: \( \boxed{\text{Kirchhoff's junction rule and loop rule}} \)
Find work done in bringing charge q = 3nC from infinity to point A as shown in the figure : 
Two capacitors \( C_1 \) and \( C_2 \) are connected in parallel to a battery. Charge-time graph is shown below for the two capacitors. The energy stored with them are \( U_1 \) and \( U_2 \), respectively. Which of the given statements is true? 
Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A): Choke coil is simply a coil having a large inductance but a small resistance. Choke coils are used with fluorescent mercury-tube fittings. If household electric power is directly connected to a mercury tube, the tube will be damaged.
Reason (R): By using the choke coil, the voltage across the tube is reduced by a factor \( \frac{R}{\sqrt{R^2 + \omega^2 L^2}} \), where \( \omega \) is the frequency of the supply across resistor \( R \) and inductor \( L \). If the choke coil were not used, the voltage across the resistor would be the same as the applied voltage.
In light of the above statements, choose the most appropriate answer from the options given below: