The reactivity of halides towards the S$_N$1 mechanism depends on the stability of the carbocation intermediate formed during the reaction:
Compound A forms a benzyl carbocation, which is highly stable due to resonance.
Compound B forms a primary carbocation, which is less stable but reacts due to iodine's leaving group strength.
Compound C forms a tertiary carbocation, which is very stable and reactive.
Compound D forms a primary carbocation, less stable but reacts due to bromine's moderate leaving group strength.
Thus, the halogens are ordered as per the leaving group stability in S$_N$1.
Calculate the potential for half-cell containing 0.01 M K\(_2\)Cr\(_2\)O\(_7\)(aq), 0.01 M Cr\(^{3+}\)(aq), and 1.0 x 10\(^{-4}\) M H\(^+\)(aq).
Let one focus of the hyperbola $ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 $ be at $ (\sqrt{10}, 0) $, and the corresponding directrix be $ x = \frac{\sqrt{10}}{2} $. If $ e $ and $ l $ are the eccentricity and the latus rectum respectively, then $ 9(e^2 + l) $ is equal to:
The largest $ n \in \mathbb{N} $ such that $ 3^n $ divides 50! is: