But-2-yne is reacted separately with one mole of Hydrogen as shown below:
A. A is more soluble than B
B. B The boiling point & melting point of $A$ are higher and lower than $B$ respectively
C. A is more polar than $B$ because dipole moment of $A$ is zero
D. $Br _2$ adds easily to $B$ than $A$
Identify the incorrect statements from the options given below:
But-2-yne is reacted separately with one mole of Hydrogen as shown below:
A. A is more soluble than B
B. B The boiling point & melting point of $A$ are higher and lower than $B$ respectively
C. A is more polar than $B$ because dipole moment of $A$ is zero
D. $Br _2$ adds easily to $B$ than $A$
Identify the incorrect statements from the options given below:
A, C & D only
- A and B only
B, C & D only
- B and C only
The Correct Option is C
Solution and Explanation
Properties of Alkenes:
- Melting Point: The melting point of trans alkene is greater than that of cis alkene due to the higher symmetry of trans isomers, which allows better packing in the solid state.
- Boiling Point: The boiling point of cis alkene is greater than that of trans alkene due to stronger intermolecular forces, as cis isomers are more polar.
- Bromine Addition: Bromine (Br2) adds more easily to cis alkene than trans alkene because of the closer proximity of substituents in cis isomers.
- Isomers: A is cis–but–2–ene, and B is trans–but–2–ene.
- Solubility: A (cis–but–2–ene) is more soluble due to its polarity, as cis isomers have a net dipole moment.
The correct answer is option (C): B, C & D only
Top Questions on Hydrogen
For hydrogen-like species, which of the following graphs provides the most appropriate representation of \( E \) vs \( Z \) plot for a constant \( n \)?
[E : Energy of the stationary state, Z : atomic number, n = principal quantum number]Consider the following data:
- Heat of formation of \( CO_2(g) \) = -393.5 kJ mol\(^{-1}\)
- Heat of formation of \( H_2O(l) \) = -286.0 kJ mol\(^{-1}\)
- Heat of combustion of benzene = -3267.0 kJ mol\(^{-1}\)
The heat of formation of benzene is ……… kJ mol\(^{-1}\) (Nearest integer).Which of the following is/are correct with respect to the energy of atomic orbitals of a hydrogen atom?
(A) \( 1s<2s<2p<3d<4s \)
(B) \( 1s<2s = 2p<3s = 3p \)
(C) \( 1s<2s<2p<3s<3p \)
(D) \( 1s<2s<4s<3d \)
Choose the correct answer from the options given below:An ideal gas undergoes a cyclic transformation starting from point A and coming back to the same point by tracing the path A→B→C→D→A as shown in the three cases below.
Choose the correct option regarding \(\Delta U\):- The ratio of magnitude of potential energy and kinetic energy for \(5^{th}\) excited state of hydrogen atom is
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Concepts Used:
Dihydrogen
Dihydrogen is the homonuclear diatomic molecule built from two hydrogen atoms. This molecule characterizes a covalent bond between two hydrogen atoms, satisfying each of their required pair configurations.
Structure of Dihydrogen:
The dihydrogen molecule characterizes a single covalent bond between the two hydrogen atoms that comprise it. This molecule has a linear shape and is nonionic in nature. Each hydrogen atom comes up with one electron towards the covalent bond.
Properties of Dihydrogen:
- At Standard Temperature and Pressure (STP), dihydrogen exists in the gaseous state.
- The melting point of H2 is 13.99 Kelvin. Transforming this value to the celsius scale, the melting point of dihydrogen can be expressed as -259.16 degrees celsius.
- The boiling point correlated with dihydrogen corresponds to 20.271 on the Kelvins scale. Transforming this value into the celsius scale, the boiling point of H2 can be represented as -252.879 degrees celsius.
- The latent heat of fusion associated with the H2 molecule correlates to 0.117 kilojoules per mole.
- The latent heat of vaporization (also known as the enthalpy of vaporization) of dihydrogen is equivalent to 0.904 kilojoules per mole.