- In the reaction between Be(OH)\(_2\) and Sr(OH)\(_2\), an ionic salt is formed. The reaction is an acid-base neutralization, where the hydroxide ions from both compounds combine to form water, leaving the cations of Be and Sr.
- Be is not present in the cationic part of the salt. Instead, it forms an ionic bond with the hydroxide ions in the product, and Sr is present in the cationic part of the salt. Therefore, option (3) is incorrect.
- The reaction is indeed an acid-base neutralization because both Be(OH)\(_2\) and Sr(OH)\(_2\) are bases. Hence, option (2) is correct.
- Be is tetrahedrally coordinated in the ionic salt, which is a characteristic of its coordination in such compounds, making option (1) correct.
- Both Be and Sr are present in the ionic salt formed from the reaction. Hence, option (4) is correct.
Thus, the incorrect statement is (3).
(b.)Calculate the potential for half-cell containing 0.01 M K\(_2\)Cr\(_2\)O\(_7\)(aq), 0.01 M Cr\(^{3+}\)(aq), and 1.0 x 10\(^{-4}\) M H\(^+\)(aq).
Match List-I with List-II.
Choose the correct answer from the options given below :