Based on VSEPR model, match the xenon compounds given in List-I with the corresponding geometries and the number of lone pairs on xenon given in List-II and choose the correct option.
List I
List II
(P) XeF2 (1) Trigonal bipyramidal and two lone pair of electrons (Q) XeF4 (2) Tetrahedral and one lone pair of electrons (R) XeO3 (3) Octahedral and two lone pair of electrons (S) XeO3F2 (4) Trigonal bipyramidal and no lone pair of electrons (5) Trigonal bipyramidal and three lone pair of electrons
List I | List II | ||
| (P) | XeF2 | (1) | Trigonal bipyramidal and two lone pair of electrons |
| (Q) | XeF4 | (2) | Tetrahedral and one lone pair of electrons |
| (R) | XeO3 | (3) | Octahedral and two lone pair of electrons |
| (S) | XeO3F2 | (4) | Trigonal bipyramidal and no lone pair of electrons |
| (5) | Trigonal bipyramidal and three lone pair of electrons | ||
- P-5, Q-2, R-3, S-1
- P-5, Q-3, R-2, S-4
- P-4, Q-3, R-2, S-1
- P-4, Q-2, R-5, S-3
The Correct Option is B
Approach Solution - 1
Step 1: Determining the Geometry and Lone Pairs of Each Xenon Compound
- (P) XeF2
- Central atom: Xe
- Valence electrons: 8
- Bonding pairs: 2 (due to 2 F atoms)
- Lone pairs: \( 8 - 2 = 6 \) (3 lone pairs)
- Geometry: Trigonal bipyramidal (linear shape due to lone pairs in equatorial positions)
- Matches: (5)
- (Q) XeF4
- Central atom: Xe
- Valence electrons: 8
- Bonding pairs: 4 (due to 4 F atoms)
- Lone pairs: \( 8 - 4 = 4 \) (2 lone pairs)
- Geometry: Octahedral (square planar shape due to lone pairs at axial positions)
- Matches: (3)
- (R) XeO3
- Central atom: Xe
- Valence electrons: 8
- Bonding pairs: 3 (due to 3 O atoms)
- Lone pairs: \( 8 - 3 = 5 \) (1 lone pair)
- Geometry: Tetrahedral (pyramidal shape due to lone pair)
- Matches: (2)
- (S) XeOF4
- Central atom: Xe
- Valence electrons: 8
- Bonding pairs: 5 (3 O atoms and 2 F atoms)
- Lone pairs: \( 8 - 5 = 3 \) (0 lone pairs)
- Geometry: Trigonal bipyramidal (no lone pairs present)
- Matches: (4)
Step 2: Conclusion
- (P) → (5)
- (Q) → (3)
- (R) → (2)
- (S) → (4)
Thus, the correct answer is (B) P-5, Q-3, R-2, S-4.
Approach Solution -2
To solve the problem, we need to use the VSEPR model to determine the molecular geometries and lone pairs on xenon compounds and match them with the given options.
1. Xenon Difluoride (XeF2):
- Total electron pairs: 5 (2 bonding pairs, 3 lone pairs)
- Geometry: Trigonal bipyramidal
- Lone pairs: 3
- Corresponds to option (5) "Trigonal bipyramidal and three lone pairs".
2. Xenon Tetrafluoride (XeF4):
- Total electron pairs: 6 (4 bonding pairs, 2 lone pairs)
- Geometry: Octahedral
- Lone pairs: 2
- Corresponds to option (3) "Octahedral and two lone pairs".
3. Xenon Trioxide (XeO3):
- Total electron pairs: 4 (3 bonding pairs, 1 lone pair)
- Geometry: Tetrahedral
- Lone pairs: 1
- Corresponds to option (2) "Tetrahedral and one lone pair".
4. Xenon Oxyfluoride (XeO3F2):
- Total electron pairs: 5 (5 bonding pairs, 0 lone pairs)
- Geometry: Trigonal bipyramidal
- Lone pairs: 0
- Corresponds to option (4) "Trigonal bipyramidal and no lone pairs".
Final Matching:
P - 5, Q - 3, R - 2, S - 4
Final Answer:
Option (B)
Top Questions on Chemical bonding and molecular structure
- Which statements are NOT TRUE about $XeO_2F_2$?
A. It has a see-saw shape.
B. Xe has 5 electron pairs in its valence shell in $XeO_2F_2$.
C. The O-Xe-O bond angle is close to $180^\circ$.
D. The F-Xe-F bond angle is close to $180^\circ$.
E. Xe has 16 valence electrons in $XeO_2F_2$.- JEE Main - 2026
- Chemistry
- Chemical bonding and molecular structure
- Given below are two statements:
Statement I: The number of pairs among [SiO₂, CO₂], [SnO, SnO₂], [PbO, PbO₂] and [GeO, GeO₂], which contain oxides that are both amphoteric is 2.
Statement II: BF₃ is an electron deficient molecule, can act as a Lewis acid, forms adduct with NH₃ and has a trigonal planar geometry.
In the light of the above statements, choose the correct answer from the options given below:- JEE Main - 2026
- Chemistry
- Chemical bonding and molecular structure
From the given following (A to D) cyclic structures, those which will not react with Tollen's reagent are :
- JEE Main - 2026
- Chemistry
- Chemical bonding and molecular structure
Compound 'P' undergoes the following sequence of reactions : (i) NH₃ (ii) $\Delta$ $\rightarrow$ Q (i) KOH, Br₂ (ii) CHCl₃, KOH (alc), $\Delta$ $\rightarrow$ NC-CH₃. 'P' is :
- JEE Main - 2026
- Chemistry
- Chemical bonding and molecular structure
- Given below are two statements: Statement I: The halogen that makes longest bond with hydrogen in HX, has the smallest covalent radius in its group.
Statement II: A group 15 element's hydride \(EH_3\) has the lowest boiling point among corresponding hydrides of other group 15 elements. The maximum covalency of that element \(E\) is 4.
In the light of the above statements, choose the correct answer from the options given below.- JEE Main - 2026
- Chemistry
- Chemical bonding and molecular structure
Questions Asked in JEE Advanced exam
- Let $ x_0 $ be the real number such that $ e^{x_0} + x_0 = 0 $. For a given real number $ \alpha $, define $$ g(x) = \frac{3xe^x + 3x - \alpha e^x - \alpha x}{3(e^x + 1)} $$ for all real numbers $ x $. Then which one of the following statements is TRUE?
- JEE Advanced - 2025
- Fundamental Theorem of Calculus
- A linear octasaccharide (molar mass = 1024 g mol$^{-1}$) on complete hydrolysis produces three monosaccharides: ribose, 2-deoxyribose and glucose. The amount of 2-deoxyribose formed is 58.26 % (w/w) of the total amount of the monosaccharides produced in the hydrolyzed products. The number of ribose unit(s) present in one molecule of octasaccharide is _____.
Use: Molar mass (in g mol$^{-1}$): ribose = 150, 2-deoxyribose = 134, glucose = 180; Atomic mass (in amu): H = 1, O = 16- JEE Advanced - 2025
- Biomolecules
Let $ P(x_1, y_1) $ and $ Q(x_2, y_2) $ be two distinct points on the ellipse $$ \frac{x^2}{9} + \frac{y^2}{4} = 1 $$ such that $ y_1 > 0 $, and $ y_2 > 0 $. Let $ C $ denote the circle $ x^2 + y^2 = 9 $, and $ M $ be the point $ (3, 0) $. Suppose the line $ x = x_1 $ intersects $ C $ at $ R $, and the line $ x = x_2 $ intersects $ C $ at $ S $, such that the $ y $-coordinates of $ R $ and $ S $ are positive. Let $ \angle ROM = \frac{\pi}{6} $ and $ \angle SOM = \frac{\pi}{3} $, where $ O $ denotes the origin $ (0, 0) $. Let $ |XY| $ denote the length of the line segment $ XY $. Then which of the following statements is (are) TRUE?
- JEE Advanced - 2025
- Conic sections
- Adsorption of phenol from its aqueous solution on to fly ash obeys Freundlich isotherm. At a given temperature, from 10 mg g$^{-1}$ and 16 mg g$^{-1}$ aqueous phenol solutions, the concentrations of adsorbed phenol are measured to be 4 mg g$^{-1}$ and 10 mg g$^{-1}$, respectively. At this temperature, the concentration (in mg g$^{-1}$) of adsorbed phenol from 20 mg g$^{-1}$ aqueous solution of phenol will be ____. Use: $\log_{10} 2 = 0.3$
- JEE Advanced - 2025
- Adsorption
- At 300 K, an ideal dilute solution of a macromolecule exerts osmotic pressure that is expressed in terms of the height (h) of the solution (density = 1.00 g cm$^{-3}$) where h is equal to 2.00 cm. If the concentration of the dilute solution of the macromolecule is 2.00 g dm$^{-3}$, the molar mass of the macromolecule is calculated to be $X \times 10^{4}$ g mol$^{-1}$. The value of $X$ is ____. Use: Universal gas constant (R) = 8.3 J K$^{-1}$ mol$^{-1}$ and acceleration due to gravity (g) = 10 m s$^{-2}\}$
- JEE Advanced - 2025
- Colligative Properties