Match the LIST-I with LIST-II.
Choose the correct answer from the options given below :
Let's analyze the molecular structures: ICl\(^-\): This ion has a central iodine atom with 2 bonding pairs and 3 lone pairs, resulting in a 2 : 3 ratio (option III). H\(_2\)O:
The oxygen atom has 2 lone pairs and 2 bonding pairs, which gives the ratio 2 : 2 (option IV). SO\(_2\):
The sulfur atom has 2 bonding pairs and 1 lone pair, leading to a 4 : 1 ratio (option II).
XeF\(_4\): The xenon atom has 4 bonding pairs and 2 lone pairs, giving the ratio 4 : 2 (option I).
Therefore, the correct matching is: A-III, B-IV, C-II, D-I.
Match the LIST-I with LIST-II
LIST-I | LIST-II |
---|---|
A. PF5 | I. dsp2 |
B. SF6 | II. sp3d |
C. Ni(CO)4 | III. sp3d2 |
D. [PtCl4]2- | IV. sp3 |
Choose the correct answer from the options given below:
Given below are two statements:
Statement I : The N-N single bond is weaker and longer than that of P-P single bond
Statement II : Compounds of group 15 elements in +3 oxidation states readily undergo disproportionation reactions.
In the light of above statements, choose the correct answer from the options given below
What is the empirical formula of a compound containing 40% sulfur and 60% oxygen by mass?
In the following circuit, the reading of the ammeter will be: (Take Zener breakdown voltage = 4 V)
If $10 \sin^4 \theta + 15 \cos^4 \theta = 6$, then the value of $\frac{27 \csc^6 \theta + 8 \sec^6 \theta}{16 \sec^8 \theta}$ is:
If the area of the region $\{ (x, y) : |x - 5| \leq y \leq 4\sqrt{x} \}$ is $A$, then $3A$ is equal to
Let $A = \begin{bmatrix} \cos \theta & 0 & -\sin \theta \\ 0 & 1 & 0 \\ \sin \theta & 0 & \cos \theta \end{bmatrix}$. If for some $\theta \in (0, \pi)$, $A^2 = A^T$, then the sum of the diagonal elements of the matrix $(A + I)^3 + (A - I)^3 - 6A$ is equal to
Let $A = \{ z \in \mathbb{C} : |z - 2 - i| = 3 \}$, $B = \{ z \in \mathbb{C} : \text{Re}(z - iz) = 2 \}$, and $S = A \cap B$. Then $\sum_{z \in S} |z|^2$ is equal to