Question:

Which of the following molecules(s) show/s paramagnetic behavior?

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Molecules with unpaired electrons are paramagnetic.
Updated On: Apr 25, 2025
  • $\mathrm{O}_{2}$
  • $\mathrm{N}_{2}$
  • $\mathrm{F}_{2}$
  • $\mathrm{S}_{2}$
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The Correct Option is D

Solution and Explanation

1. Number of unpaired electrons: 
- (A) $\mathrm{O}_{2}$: 2 
- (B) $\mathrm{N}_{2}$: 0 
- (C) $\mathrm{F}_{2}$: 0 
- (D) $\mathrm{S}_{2}$: 2 
- (E) $\mathrm{Cl}_{2}$: 0 
2. Paramagnetic behavior: - Molecules with unpaired electrons exhibit paramagnetic behavior. 
- Therefore, $\mathrm{O}_{2}$ and $\mathrm{S}_{2}$ are paramagnetic. 
Therefore, the correct answer is (4) A & D only.

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