Based on given graph between stopping potential and frequency of irradiation, work function of metal is equal to
1 eV
3 eV
2 eV
4 eV
The correct answer is option (C) : 2 eV
\(eV_5=h_v-\phi\)
On extrapolating the graph , the graph cuts the yaxis at -2
\(\Rightarrow \) at v=0,vs=-2v
\(\Rightarrow \phi = 2\,eV\)
Which of the following statements are correct, if the threshold frequency of caesium is $ 5.16 \times 10^{14} \, \text{Hz} $?
20 mL of sodium iodide solution gave 4.74 g silver iodide when treated with excess of silver nitrate solution. The molarity of the sodium iodide solution is _____ M. (Nearest Integer value) (Given : Na = 23, I = 127, Ag = 108, N = 14, O = 16 g mol$^{-1}$)
When light shines on a metal, electrons can be ejected from the surface of the metal in a phenomenon known as the photoelectric effect. This process is also often referred to as photoemission, and the electrons that are ejected from the metal are called photoelectrons.
According to Einstein’s explanation of the photoelectric effect :
The energy of photon = energy needed to remove an electron + kinetic energy of the emitted electron
i.e. hν = W + E
Where,